Answer:
[tex]A[/tex]Explanation:
Here, we want to get the number of calories Q of heat needed
Mathematically:
[tex]\begin{gathered} Q\text{ = mc}\Delta T \\ \\ m\text{ = mass = 35 g} \\ c\text{ = specific heat capacity = 0.108 cal/g}\degree C \\ \Delta T\text{ = change in temperature = \lparen35-25\rparen}\degree C\text{ = 10 }\degree C \end{gathered}[/tex]Substituting the values, we have it that:
[tex]Q\text{ = 35 }\times0.108\text{ }\times10\text{ = 37.8 cal}[/tex]