Given that the time has a continuous distribution between 43 minutes and 57 minutes.
To find the probability it takes between 50.5 minutes and 52.8 minutes, we have:
[tex]P\mleft(50.5\text{ min and 52.8 min}\mright)=\text{ }\frac{52.8-50.5}{57-43}=\frac{2.3}{14}=\text{ 0.16}43[/tex]Therefore, the probablity it takes between 50.5 min and 52.8 min is 0.
