from the equation y=20x - 47
[tex]\begin{gathered} \text{the gradient m}_1=\text{ 20 ( coeffeicient of x)} \\ \sin ce\text{ the lines are parallel} \\ m_1=m_2_{} \end{gathered}[/tex]
where m2 is the gradient of the second line
given two points (2, -4) on the line
[tex]\begin{gathered} y\text{ = mx + c} \\ y=\text{ -4, x = 2, m =20} \\ \text{substitute to obtain the intercept c} \end{gathered}[/tex][tex]undefined[/tex]
