in a right triangle as the one in the image above, you can find the value of any of the sides or the angles with the next trigonometric functions:
[tex]\begin{gathered} \sin \theta=\frac{o}{h} \\ \\ \cos \theta=\frac{a}{h} \\ \\ \tan \theta=\frac{o}{a} \end{gathered}[/tex]
You have the value of:
o = 50ft
h= 75ft
You use the frist function:
[tex]\begin{gathered} \sin \theta=\frac{50ft}{75ft} \\ \\ \theta=\sin ^{-1}(\frac{50}{75}) \\ \\ \theta=41.81º\approx42º \end{gathered}[/tex]Then, the
angle that the rope makes with the ground is approximately 42 degrees
