Respuesta :
Answer:
2.0atm
Explanations:
According to Henry's law, the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid. Mathematically;
[tex]\begin{gathered} S\alpha P \\ S=kP \\ k=\frac{S_1}{P_1}=\frac{S_2}{P_2} \end{gathered}[/tex]Given the following parameters
[tex]\begin{gathered} S_1=3.5g\text{/L} \\ P_1=0.8atm \\ S_2=8.9g\text{/L} \\ \end{gathered}[/tex]Substitute the given parameters into the formula to have:
[tex]\begin{gathered} P_2=\frac{P_1S_2}{S_1} \\ P_2=\frac{0.8atm\times8.9g\text{/L}}{3.5g\text{/L}} \\ P_2=\frac{7.12atm}{3.5} \\ P_2=2.0atm \end{gathered}[/tex]Hence the pressure needed to produce an aqueous solution containing 8.9 g/L of the same gas at 0 degrees Celsius is 2.0atm
