Given data:
Speed of car 1;
[tex]u_1=15\text{ m/s}[/tex]Speed of car 2;
[tex]u_2=20\text{ m/s}[/tex]Part (A)
Velocity time graph:
Part (B)
Displacement-time graph:
Part (C)
The displacement is given as,
[tex]s=u\times t[/tex]The displacement of car 1 after t=6 s is given as,
[tex]\begin{gathered} s_1=u_1\times(6\text{ s}) \\ =(15\text{ m/s})\times(6\text{ s}) \\ =90\text{ m} \end{gathered}[/tex]The displacement of car 2 after t=6 s is given as,
[tex]\begin{gathered} s_2=u_2\times(6\text{ s}) \\ =(20\text{ m/s})\times(6\text{ s}) \\ =120\text{ m} \end{gathered}[/tex]Therefore, the separation between the cars after 6 s is given as,
[tex]\begin{gathered} \Delta s=s_2-s_1 \\ =(120\text{ m})-(90\text{ m}) \\ =30\text{ m} \end{gathered}[/tex]Therefore, after 6 seconds the separation between the cars is 30 m.