Given,
The measure of the perpendicular is,
p = 6.
The measure of hypotenuse is,
[tex]h=\sqrt[]{85}[/tex]
The expression of the Pythagorean theorem is,
[tex]\text{hypotenuse}^2=base^2+perpendicular^2[/tex]
Substituting the measure then,
[tex]\begin{gathered} (\sqrt{85})^2=(b)^2+(6)^2 \\ 85=(b)^2+36 \\ b^2=85-36 \\ b^2=49 \\ b=\sqrt[]{49} \\ b=7 \end{gathered}[/tex]
Hence, the measure of
