ANSWER:
The initial velocity is -5.2 m/s
The height is 1.38 m
STEP-BY-STEP EXPLANATION:
We have to calculate the velocity, we must follow the following formula of the vertical movement upwards:
[tex]\begin{gathered} v_i=-g\cdot t \\ \text{where,} \\ g=\text{gravity = 9.8 }\frac{m}{s^2} \\ t=\text{time = 0.53 sec} \end{gathered}[/tex]replacing:
[tex]\begin{gathered} v_i=-9.8\cdot0.53 \\ v_i=-5.2\text{ m/s} \end{gathered}[/tex]Now, to calculate the height that the ball reached, we use the following formula:
[tex]\begin{gathered} h=\frac{-v^2_i}{2g} \\ \text{ replacing} \\ h=\frac{-\mleft(-5.2\mright)^2}{2\cdot9.8} \\ h=1.38\text{ m} \end{gathered}[/tex]