We have the following:
[tex]\begin{gathered} y=\frac{1}{2}x+1 \\ y=\frac{1}{2}x-1 \end{gathered}[/tex]we equalize the equations and we have:
[tex]\begin{gathered} \frac{1}{2}x+1=\frac{1}{2}x-1 \\ \frac{1}{2}x-\frac{1}{2}x=-1-1 \\ 0=-2 \end{gathered}[/tex]Therefore, the answer is C. there is no solution
