Since the triangle has two congruent angles, it is an isosceles triangle, so the other leg also has a length of x.
Using the Pythagorean theorem, we have:
[tex]\begin{gathered} x^2+x^2=6^2 \\ 2x^2=36 \\ x^2=18 \\ x=\sqrt[]{18}=3\sqrt[]{2} \end{gathered}[/tex]
