Two marbles are drawn one by one from a well- shuffled box containing 2 gold marbles, 6 silver marbles and 9 bronze balls. (correct to 4 decimal places)a) find the probability that they are both gold marbles if the first marble is replaced;b) find the probability that they are both silver marbles if the first marble is not replaced.

Two marbles are drawn one by one from a well shuffled box containing 2 gold marbles 6 silver marbles and 9 bronze balls correct to 4 decimal placesa find the pr class=

Respuesta :

Answer:

a) 0.0138

b) 0.1103

Explanations:

Probability is the likelihood or chance that an event will occur. Mathematically;

[tex]Probability=\frac{n(E)}{n(S)}[/tex]

where:

n(S) is the total outcome

n(E) is the total number of events

If a well- shuffled box contains 2 gold marbles, 6 silver marbles and 9 bronze balls, the total outcome is given as:

n(S) = 2 + 6 + 9

n(S) = 17 marbles

a) If the marbles selected are two gold marbles and replaced, the probability of selecting two gold marbles will be:

[tex]\begin{gathered} Pr(2\text{ gold marbles})=\frac{2}{17}\times\frac{2}{17} \\ Pr(2\text{ gold marbles})=\frac{4}{289} \\ Pr(2\text{ gold marbles})\approx0.0138 \end{gathered}[/tex]

b) If two silver marbles are selected, the probability of selceting the first silver marble is given as:

[tex]Pr(first\text{ silver marble})=\frac{6}{17}[/tex]

If the first silver marble is not replaced, the probability of picking the second one will be:

[tex]Pr(second\text{ silver marble})=\frac{6-1}{17-1}=\frac{5}{16}[/tex]

The probability that they are both silver marbles if the first marble is not replaced is calculated as:

[tex]\begin{gathered} Pr(2\text{ silver marbles})=\frac{\cancel{6}^3}{17}\times\frac{5}{\cancel{16}^8} \\ Pr(2\text{ silver marbles})=\frac{15}{136} \\ Pr(2\text{ silver marbles})\approx0.1103 \end{gathered}[/tex]

Hence the probability that they are both silver marbles if the first marble is not replaced is 0.1103