The initial population given is
[tex]=13[/tex]
The percentage growth rate is
[tex]\begin{gathered} r=6^{} \\ r=\frac{6}{100}=0.06 \end{gathered}[/tex]
The Exponential function is given as
[tex]\begin{gathered} y=ab^x \\ \text{where,} \\ a=\text{initial growth}=13 \\ b=\text{growth rate=(1+r)} \\ x=Number\text{ of years=11} \end{gathered}[/tex]
By substituting the values, we will have the exponential formula to be
[tex]\begin{gathered} y=ab^x \\ y=a(1+r)^x \\ y=a(1+0.06)^x \\ y=a(1.06)^x \end{gathered}[/tex]
By substituting the values of a and x in the formula above, we will have
[tex]\begin{gathered} y=a(1.06)^x \\ y=13(1.06)^{11} \\ y=13\times1.898298558 \\ y=24.67788126 \\ y\approx(2\text{ d.p)} \\ y\approx24.68 \end{gathered}[/tex]
Therefore,
The final answer is = 24.68
