The system of equations is given to be:
[tex]\begin{gathered} 4x+5y=35\text{ ----------------(1)} \\ x-2y=-1\text{ ---------------(2)} \end{gathered}[/tex]Step 1: Make x the subject of the formula in equation (2)
[tex]x=2y-1\text{ ---------------(3)}[/tex]Step 2: Substitute for x as calculated in equation (3) into equation (1)
[tex]4(2y-1)+5y=35[/tex]Step 3: Solve the equation from Step 2
[tex]\begin{gathered} 8y-4+5y=35 \\ 13y=35+4 \\ 13y=39 \\ y=\frac{39}{13} \\ y=3 \end{gathered}[/tex]Step 4: Substitute the value of y into equation (3) to get x
[tex]\begin{gathered} x=2(3)-1 \\ x=6-1 \\ x=5 \end{gathered}[/tex]SOLUTION
[tex](x,y)=(5,3)[/tex]