We are given two points from the question
(0, 0) because the line passes through the origin and (5, -12)
From the given points
x1 = 0, y1 = 0, x2 = 5, and y2 = -12
[tex]\begin{gathered} Dis\tan ce\text{ = }\sqrt[]{(x1-x2)^2+(y1-y2)^2} \\ \text{Distance = }\sqrt[]{(0-5)^2+(0-(-12)\rbrack^2} \\ =\text{ }\sqrt[]{(-5)^2+(12)^2} \\ =\text{ }\sqrt[]{25\text{ + 144}} \\ =\text{ }\sqrt[]{169} \\ =\text{ 13} \end{gathered}[/tex]
The distance between the origin and point (5, -12) is 13
The answer is 13, OPTION D
