A rectangular park is enclosed by picket fencing. The park directorg voted to get so half of the park for a triangular mawer garden. A diagram of the rectangular park and the set as de flower garden is shown below.


The length of the diagonal shown in the picture is computed with help of the Pythagorean theorem, as follows:
c² = a² + b²
c² = 48² + 20²
c² = 2304 + 400
c² = 2704
c = √2704
c = 52 ft
The perimeter of the original flower garden is:
20 + 48 + 52 = 120 ft
The perimeter of the original park is:
2*20 + 2*48 = 136 ft
The scale factor that transforms the original park into the bigger one is:
[tex]\frac{\text{ new length of a side}}{\text{ original length of a side}}=\frac{30\text{ ft}}{20\text{ ft}}=\frac{3}{2}[/tex]The perimeter of the new park will be:
[tex]\text{original perimeter}\cdot scale\text{ factor = 136}\cdot\frac{3}{2}=204\text{ ft}[/tex]Then, the fencing needed to enclose the larger park is:
204 - 136 = 68 ft
The perimeter of the new flower garden will be:
[tex]120\cdot\frac{3}{2}=180\text{ ft}[/tex]From the 68 ft needed to enclose the larger park, 68/2 = 34 ft are used to enclose the larger flower garden. Then, the fencing needed to enclose the larger flower garden is:
180 - 120 - 34 = 26 ft