Part B:
The solution in Part 1 is -39.1, so we can berak this result in tens, ones and theths so:
[tex]\begin{gathered} \text{tens}\to30 \\ \text{ones}\to9 \\ \text{theths}\to0.1 \end{gathered}[/tex]So if we sum the we have the same answer
[tex]30+9+0.1=39.1[/tex]Part C:
the operation we can rewrite is:
[tex]T=72.3+(-111.4)=(70+2+0.3)+(-100-10-1-0.4)[/tex]and using the distribution propertie we can write it like:
[tex]T=-100+(70-10)+(2-1)+(0.3-0.4)[/tex]Part D:
and then we operate using the assosiative propertie:
[tex]T=-100+60+1-0.1[/tex]Part E:
Finally we simplyfy the expression:
[tex]T=-100+60+1-0.1=-39.1[/tex]Part F:
now he meassure the temperature of the water and it dropes -0.6 Fº so we have to rest this to the last temperature so:
[tex]-39.1-0.6=-39.7[/tex]