Given:
Speed of sound, v = 344 m/s
Low frequency, fl = 30 Hz.
High frequency, fh = 25 kHz.
Let's find the audible range of sound spectrum.
The range of sound can be said to be the wavelength.
To find the wavelength, apply the formula:
[tex]\lambda=\frac{v}{f}[/tex]Where:
• λ is the wavelength in meters (m).
,• v is the speed in meters per second (m/s)
,• f is the frequency (Hz.)
• To find the largest wavelength, we have:
[tex]\begin{gathered} \lambda_L=\frac{v}{f_s} \\ \\ \lambda_L=\frac{344}{30} \\ \\ \lambda_L=11.47\text{ m} \end{gathered}[/tex]• To find the smallest wavelength, we have:
[tex]\begin{gathered} \lambda_s=\frac{v}{f_h} \\ \\ \lambda_s=\frac{344}{25\times10^3} \\ \\ \lambda_s=0.014\text{ m} \end{gathered}[/tex]Therefore, we have:
Smallest value: 0.014 m
Largest value: 11.47 m
ANSWER:
• Smallest value: , 0.014 m
,• Largest value: , 11.47 m
