Given the equation:
[tex]4x^2-12=3x\text{ ----- equation 1}[/tex]Required: sum and product of the roots of the equation
solution:
For a quadratic equation of the form
[tex]ax^2\text{ + bx + c = 0 ------ equation 2}[/tex]the sum of the roots is expressed as
[tex]\text{sum of roots = -}\frac{b}{a}[/tex]the product of the roots is expressed as
[tex]\text{product of roots = }\frac{c}{a}[/tex]The given quadratic equation can be rewritten in the form as in equation 2 to be
[tex]4x^2-3x-12\text{ = 0 ----- equation 3}[/tex]In comparison to equation 2,
[tex]\begin{gathered} a\text{ = 4} \\ b\text{ = -3} \\ c\text{ =-12} \end{gathered}[/tex]Thus,
Sum of roots:
[tex]\begin{gathered} \text{sum of roots = -}\frac{b}{a} \\ =-\frac{-3}{4} \\ =\frac{3}{4} \end{gathered}[/tex]thus, the sum of the roots is
[tex]\frac{3}{4}[/tex]Products of roots:
[tex]\begin{gathered} \text{product of roots = }\frac{c}{a} \\ =\frac{-12}{4} \\ =-3 \end{gathered}[/tex]thus, the product of the roots is
[tex]-3[/tex]
