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average force exerted by the ground on the object. (1 point)A. 06.8 NB. O10.563 NC. 09.048 ND. O 12.856 NE. O 3.149 N5. An object was acted upon by a force of 24 for 0.8seconds. Calculate the change in its momentum. (1 point)A. O 33.836 kg m/sB. O 31.903 kg m/sC. O 12.883 kg m/sD. O 19.2 kg m/sE. O 23.979 kg m/sAn obiect of mass 05 kg was acted by a force of 14 2N forE

average force exerted by the ground on the object 1 pointA 068 NB O10563 NC 09048 ND O 12856 NE O 3149 N5 An object was acted upon by a force of 24 for 08second class=

Respuesta :

The change in the momentum is basically the impulse. The impulse is given by:

[tex]\Delta m=I=F\cdot\Delta t[/tex]

Where:

[tex]\begin{gathered} F=24N \\ \Delta t=0.8s \\ Therefore: \\ I=24\cdot0.8=19.2\cdot kg\frac{m}{s} \end{gathered}[/tex]

Answer:

D. 19.2 kg m/s

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