Given the Quadratic Equation:
[tex]x^2=-7x+7[/tex]
You need to rewrite it in this form:
[tex]ax^2+bx+c=0[/tex]
Then, you need to move the terms on the right side to the left side (remember to change their signs):
[tex]x^2+7x-7=0[/tex]
Now you can identify that:
[tex]\begin{gathered} a=1 \\ b=7 \\ b=-7 \end{gathered}[/tex]
In order to find the type of roots or solutions the Quadratic Equation has, you can find the Discriminant using this formula:
[tex]D=b^2-4ac[/tex]
By substituting values into the formula and evaluating, you get:
[tex]D=(7)^2-(4)(1)(-7)=77[/tex]
By definition, if:
[tex]D>0[/tex]
The Quadratic Equation has two different Real Roots.
Hence, the answer is: Option c.
