I believe you need to use the quadratic formula for this one, but I am not sure!

To solve the value of x in the above equation, here are the steps.
1. Subtract 13 on both sides of the equation.
[tex]\begin{gathered} 4x^2+13-13=49-13 \\ 4x^2=36 \end{gathered}[/tex]2. Divide both sides of the equation by 4.
[tex]\begin{gathered} \frac{4x^2}{4}=\frac{36}{4} \\ x^2=9 \end{gathered}[/tex]3. Get the square root on both sides of the equation.
[tex]\begin{gathered} \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}[/tex]The possible values of x are +3 and -3. The smaller value is -3.