The slope of line is m = 3.
The line passing through point (-4,7).
The general equation for point-slope form of equation is,
[tex]y-y_1=m(x-x_1)[/tex]Determine the equation for m = 3 and point (-4,7).
[tex]y-7=3(x+4)[/tex]Thus, point-slope form of equation is y - 7 = 3(x + 4).
Simplify the point-slope form of equatio to ontain the slope-intercept form of equation.
[tex]\begin{gathered} y-7=3(x+4) \\ y=3x+12+7 \\ y=3x+19 \end{gathered}[/tex]Thus, equation of line in slope-intercept form is y = 3x + 19.
