ANSWER:
EXPLANATION
Given that:
[tex]\text{ The molar solubility of silver sulfide is 1.53 x 10}^{-5}[/tex]
To find the solubility constant product for the compound, follow the steps below
Step 1: Write the ionic equation for silver sulfite
[tex]Ag_2SO_3\rightarrow\text{ 2Ag}^+\text{ + SO}_3^{2-}[/tex]
From the above reaction, the silver sulfite split into silver ion and sulfite ion
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