Given:
Radius = 5/6
Angle
[tex]\theta=\frac{2\pi}{3}\text{ radians}[/tex]
Required:
Find the area of the sector.
Explanation:
The area of the sector is given by the formula:
[tex]A=\frac{1}{2}r^2\theta[/tex]
Substitute the given values in the formula.
[tex]\begin{gathered} A=\frac{1}{2}\times(\frac{5}{6})^2\times\frac{2\pi}{3} \\ =\frac{1}{2}\times\frac{25}{36}\times\frac{2\pi}{3} \\ =\frac{25\pi}{108}\text{ sq unit} \end{gathered}[/tex]
Final Answer:
Thus the area of the sector is
[tex]\frac{25\pi}{108}[/tex]
