To give all possible results, this is the sample space of the distribution ;
Event A, the sum is greater than 8.
The total possible outcomes is 36.
The sum being greater than 8 happens 10 times.
Therefore, the probability that the sum is greater than 8 is;
[tex]\begin{gathered} \\ \frac{10}{36}=\frac{5}{18} \end{gathered}[/tex]
Event B, The sum is dividible by 4.
In the sample space, there are 9 places where the sum is divisible by 4.
Therefore, the probability that the sum is divisible by 4 is;
[tex]\frac{9}{36}=\frac{1}{4}[/tex]
