In order to solve the equation, since it is already factored, we just need to find the value of x that makes the factors be equal zero. So we have that:
[tex]\begin{gathered} (2x+3)(x-1)=0 \\ (2x+3)=0\to2x=-3\to x=-\frac{3}{2} \\ (x-1)=0\to x=1 \end{gathered}[/tex]So the solution is {-3/2, 1}.
The solution with the highest value is x = 1.
