Given:
The mass of the sample is
[tex]m=200\text{ g}[/tex]The initial temperature is
[tex]t_i=50\text{ }\degree C[/tex]The final temperature is
[tex]t_f=80\text{ }\degree C[/tex]The amount of heat is,
[tex]H=100\text{ cal}[/tex]To find:
The specific heat capacity of the metal
Explanation:
Let the specific heat capacity is 'c'
The amount of heat for the temperature change is,
[tex]H=mc(t_f-t_i)[/tex]Substituting the values we get,
[tex]\begin{gathered} 100=200\times c\times(80-50) \\ 100=200\times c\times30 \\ c=\frac{100}{200\times30} \\ c=0.016\text{ cal/g.}\degree C \end{gathered}[/tex]Hence, the specific heat capacity is
[tex]0.016\text{ cal/g.}\degree C[/tex]