Solution:
Given the scatterplot below:
where the line of best fit is expressed as
[tex]y=0.91x+7.99[/tex]
A) Predicted hourly rate for cashier with 9 years of experience:
Thus, we have
[tex]x=9[/tex]
By substituting the value of 9 for x into the equation, we have
[tex]\begin{gathered} y=0.91\left(9\right)+7.99 \\ =\$16.18 \end{gathered}[/tex]
B) Predicted hourly rate for cashier with no experience:
This implies that
[tex]x=0[/tex]
By substitution, we have
[tex]\begin{gathered} y=0.91(0)+7.99 \\ \Rightarrow y=\$7.99 \end{gathered}[/tex]
C) Predicted increase in the hourly rate for an increase of one year of experience:
Recall that the equation of a line is expressed as
[tex]\begin{gathered} y=mx+c \\ where \\ m\Rightarrow slope \\ m=\frac{increase\text{ in y}}{increase\text{ in x}} \end{gathered}[/tex]
From the equation of the line of best fit, by comparison, we have
[tex]\begin{gathered} slope=0.91 \\ where \\ slope=\frac{incresre\text{ in hourly pay}}{increase\text{ in year of experince}} \\ \Rightarrow0.91=\frac{increase\text{ in hourly pay}}{1} \\ thus,\text{ we have} \\ predicted\text{ increase in hourly pay = \$0.91} \\ \end{gathered}[/tex]
