midpoint= (1, 1)
Xm = 1 Ym = 1
G( -4, 6)
This implies that;
x₂= -4 y₂ = 6
Let the coordinates of F by (x₁ y₁)
[tex]x_m=\frac{x_1+x_2}{2}[/tex]
Xm = 1 x₂= -4
substitute in the above and then solve for x₁
That is;
[tex]1=\frac{x_1-4}{2}[/tex]
2 = x₁ - 4
add 4 to both-side of the equation
6 = x₁
x₁=6
Similarly;
[tex]y_m=\frac{y_1+y_2}{2}[/tex]
Ym= 1 y₂= 6
substitute the value in the above and solve for y₁
That is;
[tex]1=\frac{y_1+6}{2}[/tex]
2= y₁ + 6
subtract 6 from both-side of the equation
2-6 =y₁
-4 = y₁
y₁= -4
The coordinates of F are ( 6, -4)
