Given:
The system of the equation is,
[tex]\begin{gathered} 2x+5y=0 \\ x+6y=14 \end{gathered}[/tex]Draw the lines on the graph, the point at which the lines intersects. That point will be the solution of the system.
The points on the line 2x+5y=0 are,
[tex]\begin{gathered} 2x+5y=0 \\ x=0\Rightarrow y=0 \\ x=5\Rightarrow y=-2 \\ x=-10\Rightarrow y=4 \end{gathered}[/tex]And the points on the line x+6y=14
[tex]\begin{gathered} x+6y=14 \\ x=0\Rightarrow y=\frac{7}{3} \\ x=14\Rightarrow y=0 \\ x=-10\Rightarrow y=4 \end{gathered}[/tex]The graph of the lines is,
As the point of intersection is ( -10,4).
The solution of the given system of equation is x = -10, y = 4.
