Given:
The position of the small plane is given by,
[tex]x(t)=1.64t^2[/tex]
Explanation:
The accelration of plane can be obtained by double derivative of the position function.
Determine the double derivative of the position function.
[tex]\begin{gathered} \frac{d^2}{dt^2}x(t)=\frac{d^2}{dt^2}(1.64t^2) \\ a(t)=1.64\cdot\frac{d}{dt}(2t) \\ =3.28\cdot1 \\ =3.28 \end{gathered}[/tex]
So acceleration of the small plane is 3.28 m/s^2
Answer: 3.28
