Given:
[tex]f(x)=3x^3+4x^2-10x+7[/tex]
Required:
To find the slope of the tangent line to the graph of each function at x= -1.
Explanation:
Consider the given function
[tex]f(x)=3x^3+4x^2-10x+7[/tex][tex]f^{\prime}(x)=9x^2+8x-10[/tex]
At x=-1,
[tex]\begin{gathered} f^{\prime}(-1)=9(-1)^2+8(-1)-10 \\ \\ =9-8-10 \\ \\ =-9 \end{gathered}[/tex]
Final Answer:
The slope is -9.
