The equation of the line that forms the hypotenuse can be gotten, we can utilize two points on that line
[tex](0,5)\text{ and (4,2)}[/tex]
We employ the equation of a line in 2 point form
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]
Put in the points, we have
[tex]\begin{gathered} \frac{y-5}{x-0}=\frac{2-5}{4-0} \\ \frac{y-5}{x}=\frac{-3}{4} \\ 4(y-5)=-3x \\ 4y-20=-3x \\ 4y+3x=20 \end{gathered}[/tex]
The equation of the line is,
4y + 3x = 20
