u√2
Explanation:The mass, m = 100 g
m = 100/1000 g
m = 0.1 kg
Using the equation of motion below for upward motion
[tex]\begin{gathered} v_f^2=v_i^2-2gH \\ \\ where: \\ v_f=final\text{ velocity} \\ \\ v_i=initial\text{ velocity} \\ \\ H=height \end{gathered}[/tex]At maximum height, vf = 0 m/s
[tex]\begin{gathered} 0=v_i^2-2gH \\ \\ v_i^2=2gH \\ \\ v_i=\sqrt{2gH} \end{gathered}[/tex]When maximum height, H = s, initial velocity = u
[tex]v_i=\sqrt{2gs}\text{ = u}[/tex]When maximum height, H = 2s
[tex]\begin{gathered} v_i=\sqrt{2g(2s)} \\ \\ v_i=\sqrt{4gs} \\ \\ v_i=\sqrt{2}\times\sqrt{2gs} \\ \\ v_i=\sqrt{2}u \\ \\ v_i=u\sqrt{2} \end{gathered}[/tex]The initial velcoity that the stone has to be projected with to reach a maximum height of 2s = u√2
