The point-slope form of the linear equation is
[tex]y-y_1=m(x-x_1)[/tex]
m is the slope
(x1, y1) is a point on the line
Since a line passes through the point (-9, 8) and has a slope of -2/3, then
[tex]\begin{gathered} (x_1,y_1)=(-9,8) \\ m=-\frac{2}{3} \end{gathered}[/tex]
Substitute them in the form above
[tex]\begin{gathered} y-8=-\frac{2}{3}(x--9) \\ y-8=-\frac{2}{3}(x+9) \end{gathered}[/tex]
The equation of the line in the point-slope form is
[tex]y-8=-\frac{2}{3}(x+9)[/tex]
