Given:
Uniform Distribution lies between 0.5 and 3.00 inches.
The mean amount of rainfall for the month is 1.75.
Required:
Standard deviation.
Explanation:
The standard deviation is given as,
[tex]\begin{gathered} \sigma\text{ = }\sqrt{\frac{\left(b-a\right)^2}{12}} \\ \\ \end{gathered}[/tex]The standard deviation is calculated as,
[tex]\begin{gathered} \sigma=\sqrt{\frac{\text{\lparen3-0.5\rparen}^2\text{{}}}{\text{12}}} \\ \sigma=\sqrt{\frac{6.25}{12}} \\ \sigma=\sqrt{0.521} \\ \sigma=0.723 \\ \end{gathered}[/tex]Answer:
Thus the standard deviation of the given data set is 0.723.
