Answer:
Volume = 13.06 L
Explanation:
We are given: mass of nitrogren gas = 16.34 g
We know: molar mass of nitrogen gas = 28.014 g/mol
: ideal gas law constant = 0.082 L.atm/K.mol
At STP: temperature = 273.15 K
: pressure = 1 atm
We first determine the number of moles of nitrogen gas:
n = m/M
= 16.34/28.014
= 0.58 mol
Using the ideal gas law:
[tex]\begin{gathered} PV\text{ = nRT} \\ \\ \therefore V\text{ = }\frac{nRT}{P}\text{ = }\frac{0.58\times0.082\times273.15}{1}\text{ = 13.06 L} \end{gathered}[/tex]
