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[tex] \frac{6}{x - 3} = \frac{3}{x} [/tex]Solve for x,and determine if the solution is extraneous or notAnswer options:A. x= -2. extraneous B. x= -2, non-extraneous C. x= -3. non-extraneous D. x= -3. extraneous

Respuesta :

We will have the following:

[tex]\frac{6}{x-3}=\frac{3}{x}\Rightarrow6x=3x-9\Rightarrow3x=-9[/tex][tex]\Rightarrow x=-3[/tex]

We will have that the solution is x = -3 and is non-extranepus. [When replace the function is solved]

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