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2. A train travels a distance of 30 km with a uniform speed of 54 km/h.It travels another distance of 50 km with a uniform speed of 90 km/h.Calculate the average speed of the train.

Respuesta :

The average speed is defined as:

[tex]v=\frac{d}{t}[/tex]

Then for the first 30 km it took:

[tex]t=\frac{30}{54}=0.556[/tex]

hours.

The second distance of 50 km took:

[tex]t=\frac{50}{90}=0.556[/tex]

Therefore the average speed is:

[tex]v=\frac{30+50}{0.556+0.556}=72[/tex]

72 km/h.

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