SOLUTION
The clerk sold three piece of troupe of ribbon to three customers
The lenght receive by each customer is
[tex]\begin{gathered} 5\frac{7}{27}yards\text{ } \\ 1\frac{6}{7}yards \\ \text{and } \\ 14\frac{1}{9}yards \end{gathered}[/tex]The total lenght of the type of Ribbon is gotten by suming the lenght of each yards received by the customers
Hence we have
[tex]\begin{gathered} \text{The total lenght is } \\ (5\frac{7}{27}+1\frac{6}{7}+14\frac{1}{9})yards \end{gathered}[/tex]Then we add the whole numbers together and the fraction
[tex](5+1+14)(\frac{7}{27}+\frac{6}{7}+\frac{1}{9})[/tex][tex]\begin{gathered} 20(\frac{49+162+21}{189}) \\ \text{where LCM=189} \end{gathered}[/tex]Then we have
[tex]\begin{gathered} 20\frac{232}{189} \\ 20(1\frac{43}{189}) \end{gathered}[/tex]Then by adding the whole numbers we obtain
[tex]21\frac{43}{189}[/tex]Therefore the lenght of type of ri