Customers of a phone company can choose between two service plans for long-distance calls. The first plan has a $26 monthly fee and charges an additional 0.11 for each minute of calls. The second plan has a $22 monthly fee and charges an additional 0.15 for each minute of calls. For how many minutes of calls will the costs of the two plans be equal?

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ANSWER

[tex]\begin{equation*} 100\text{ minutes} \end{equation*}[/tex]

EXPLANATION

Let the number of minutes of calls be x.

For the first plan, the cost of the calls is $26 monthly plus an additional $0.11 for each minute of calls. This implies that the cost of calls for the first plan is:

[tex]C_1=26+0.11x[/tex]

For the second plan, the cost of the calls is $22 monthly plus an additional $0.15 for each minute of calls. This implies that the cost of calls for the second plan is:

[tex]C_2=22+0.15x[/tex]

When the costs of the two plans are equal, it implies that C1 is equal to C2:

[tex]\begin{gathered} C_1=C_2 \\ \Rightarrow26+0.11x=22+0.15x \end{gathered}[/tex]

Now, we have to solve for x to find the number of minutes of calls for which the costs will be the same:

[tex]\begin{gathered} 26+0.11x=22+0.15x \\ 26-22=0.15x-0.11x \\ 4=0.04x \\ x=\frac{4}{0.04} \\ x=100\text{ minutes} \end{gathered}[/tex]

That is the answer.