Please help with this question:Solve for p.a = 6 + mp^2 A. p = a −6 / mB. p = ±a−6 / m−−−√C. p = ±a−6 √mD. p = a−6/2m

In order to solve for p from the given equation, you can follow these steps:
a = 6 + mp²
1. subtract 6 on both sides:
a - 6 = 6 - 6 + mp²
a - 6 = mp²
2. Divide both sides by m:
[tex]\begin{gathered} \frac{a-6}{m}=\frac{mp^2}{m} \\ \frac{a-6}{m}=p^2 \end{gathered}[/tex]
3. Take the square root on both sides, dont forget to add the ±
[tex]\begin{gathered} \sqrt{\frac{a-6}{m}}=\sqrt{p^2} \\ \pm\sqrt{\frac{a-6}{m}}=p \\ p=\pm\sqrt{\frac{a-6}{m}} \end{gathered}[/tex]Then, the second option is the correct answer
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