SOLUTION:
Given the functions;
[tex]\begin{gathered} f(x)=x^2-16 \\ \\ g(x)=x+4 \end{gathered}[/tex]
Then, we have;
[tex]\begin{gathered} (\frac{f}{g})(x)=\frac{f(x)}{g(x)} \\ \\ (\frac{f}{g})(x)=\frac{x^2-16}{x+4} \end{gathered}[/tex]
Then, simplify further;
[tex]\begin{gathered} (\frac{f}{g})(x)=\frac{(x+4)(x-4)}{x+4} \\ \\ (\frac{f}{g})(x)=x-4 \end{gathered}[/tex]
ANSWER:
[tex](\frac{f}{g})(x)= x-4[/tex]
