Given:
Initial speed = 8 m/s
Distance covered = 30 m
Mass of elevator = 500 kg
Let's find the net force the elevator experienced.
,Apply the formula below to find the acceleration:
[tex]v^2=u^2+2as[/tex]
Where:
v is the fainal velocity = 0 m/s
u is the initial velocity = 8 m/s
s = 30 m
Thus, to solve for the acceleration, a, we have:
[tex]\begin{gathered} a=\frac{v^2-u^2}{2s} \\ \\ a=\frac{0^2-8^2}{2\times30} \\ \\ a=\frac{-64}{60} \\ \\ a=-1.067m/s^2 \end{gathered}[/tex]
The acceleration of the elevator is -1.067 m/s².
Now, to find the Net force, apply the formula:
[tex]F=ma[/tex]
Where:
F is the net force
m is the mass = 500 kg
a = -1.067 m/s².
We have:
[tex]\begin{gathered} F=500\times(-1.067) \\ \\ N=-533.33\text{ N} \end{gathered}[/tex]
Therefore, the net force is 533.33 N upward.
ANSWER:
533.33 N upward.
