Given data:
The given edge of the cube is a=4 inches.
The expression for the area of the cross-section is,
[tex]A=a^2[/tex]Substitute the given value in the above expression.
[tex]\begin{gathered} A=(4in)^2 \\ =16in^2 \end{gathered}[/tex]The perimeter of one of the face is,
[tex]P=4a[/tex]Substitute the givenn value in the above expression.
[tex]\begin{gathered} P=4(\text{ 4 in)} \\ =16\text{ in} \end{gathered}[/tex]Thus, the area one of the face is 16 square-in, and perimeter one of face is 16 inches.
