Answer: C. 5
First, we will find the distance between P and R:
[tex]d=\sqrt{(-1-(-3))^2}=\sqrt{4}=2[/tex]
Since the distance between P and R is 2, given that the ratio of PR to RQ is 1:3
[tex]\begin{gathered} \frac{1}{3}=\frac{2}{x} \\ x=(2)(3) \\ x=6 \end{gathered}[/tex]
The distance between R and Q is 6. Therefore, from -1, we will add 6 units to the left to find the x-coordinate of Q:
[tex]Q_x=-1+6=5[/tex]
Therefore, the x-coordinate of Q is 5.
