The angular acceleration of the potter's wheel = 0.023 rad/s²
Explanation:At rest, the angular speed, w₀ = 0 rad/s
Final angular speed, w = 0.10 rev/s
Convert 0.10 rev/s to rad/s
[tex]\begin{gathered} w=0.10\times2\pi\text{ rad/s} \\ w=0.10\times2\times3.142 \\ w=0.6284\text{ rad/s} \end{gathered}[/tex]Time, t = 27.7 s
To find the angular acceleration, use the equation:
[tex]w=w_0+\alpha t[/tex]Substitute w = 0.6284 rad/s, w₀ = 0 rad/s, and t = 27.7 s into the equation above
[tex]\begin{gathered} w=w_0+\alpha t \\ 0.6284=0+\alpha(27.7) \\ 27.7\alpha=0.6284 \\ \alpha=\frac{0.6284}{27.7} \\ \alpha=0.023rad/s^2 \end{gathered}[/tex]The angular acceleration of the potter's wheel = 0.023 rad/s²
