SOLUTION
From the question given,
The radius r is
[tex]r=\frac{diameter}{2}=\frac{8}{2}=4[/tex]
Hence the radius of the cone is 4 in.
The height of the cone is the perpendicular height you see which is 10 in.
Hence the height of the cone is 10 in.
Volume of a cone V is given by the formula
[tex]\begin{gathered} V=\frac{1}{3}\pi\text{r}^2h \\ where\text{ r = radius = 4 in.} \\ h=\text{ height = 10 in } \\ \pi=3.14 \end{gathered}[/tex]
Solving we have
[tex]\begin{gathered} V=\frac{1}{3}\times3.14\times4^2\times10 \\ V=\frac{1}{3}\times3.14\times16\times10 \\ V=167.4666 \\ V=167.5\text{ in}^3\text{ to the nearest tenth } \end{gathered}[/tex]
Hence Volume of the cone is
[tex]V=167.5\text{ in}^3\text{ }[/tex]
So write it as 167.5 in 3
