We will employ the compound angle formula;
[tex]\tan (A-B)=\frac{\tan A-\tan B}{1+(\tan A)(\tan B)}[/tex]
We substitute the values for tanA and tanB to obtain;
[tex]\tan (A-B)=\frac{\frac{4}{3}-\frac{3}{5}}{1-\frac{4}{3}(\frac{3}{5})}[/tex]
After rearranging and simplifying, we obtain;
[tex]\tan (A-B)=+\frac{11}{3}[/tex]
