Using the slope intercept form, 1/3 is the slope of the line and (0,14/3) is an ordered pair, which is a point on the line.
What is the slope and a point the given equation of line?
The slope intercept form an equation of line is expressed as;
y = mx + b
Where m is the slope and b is the y-intercept ( a point ).
Given the equation of line;
y - 3 = (1/3)(x+5)
To convert to slope intercept form, solve for y.
y - 3 = (1/3)(x+5)
y - 3 = (1/3)(x) + (1/3)(5)
y - 3 = (1/3)(x) + 5/3
y = (1/3)(x) + 5/3 + 3
y = (1/3)(x) + 14/3
Hence, using the slope intercept form, 1/3 and 14/3 are the slope and y-intercept of the line respectively.
Next, we find a point b plugging and x value and getting a y-value.
y = (1/3)(x) + 14/3
Let x = 0
y = (1/3)(0) + 14/3
y = 14/3
Hence, (0,14/3) this forms an ordered pair, which is a point on the line.
Using the slope intercept form, 1/3 is the slope of the line and (0,14/3) is an ordered pair, which is a point on the line.
Learn more about slope and y-intercepts here: https://brainly.com/question/19824331
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